ALL the CTFS of Crypto2025 finally
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19
crypto-asimmetric/RSA-6/chall.py
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19
crypto-asimmetric/RSA-6/chall.py
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from Cryptodome.Util.number import bytes_to_long, getPrime, inverse
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from secret import flag
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p, q = getPrime(512), getPrime(512)
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n = p*q
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e = 65537
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m = bytes_to_long(flag.encode())
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print(pow(m, e, n))
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for _ in range(3):
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req = input()
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if req[0] == 'e':
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print(pow(int(req[1:]), e, n))
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elif req[0] == 'd':
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phi = (p-1)*(q-1)
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d = inverse(e, phi)
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dec = pow(int(req[1:]), d, n)
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assert dec != m
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print(dec)
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