9 lines
213 B
Python
9 lines
213 B
Python
from Crypto.Util.number import bytes_to_long, getPrime
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from secret import flag
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p, q = getPrime(512), getPrime(512)
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n = p*q
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e = [31, 71]
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print(n)
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m = bytes_to_long(flag.encode())
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print([pow(m, ee, n) for ee in e])
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